Question

Eliminate thita from the following x=4sec thita y=3tan thita​

Answer 1

Step-by-step explanation:

We have,

$x = 4 \sec( \theta) \: \: and \: \: y = 3 \tan(\theta)$

$\implies \frac{x}{4} = \sec(\theta) \: \: and \: \: \frac{y}{3} = \tan(\theta)$

Now, we know that

$\sec^{2} (\theta) - \tan^{2} (\theta) = 1$

$\implies { (\frac{x}{4} )}^{2} - {( \frac{y}{3}) }^{2} = 1$

$\implies \frac{ {x}^{2} }{16} - \frac{ {y}^{2} }{9} = 1$