Question

A 1200 kg truck is moving with a velocity of 4 m/s. It takes 3 second to stop after the brakes are applied. Calculate the force exerted by the brakes

Answer 1

Answer:

v=0, u=4, a=?,. t=3

v=u+at

0=4+3a

a=-4/3(deceleration)

F=1200×-4/3=-1600N(opposite to direction of Motion)

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