Question

A 120m long train is crosses the platform double its length in 30sec. what is the speed of the train

Answer 1

platform length = 120m+120m = 240m

Total distance= d = Train's length + platform length
=120m+240m
=360m
Time = t = 30sec
speed = ?

V = d/t
V = 360/30
V = 12 m/s

Answer 2

Given,

A 120m long train crosses the platform double its length in 30sec.

To Find,

The speed of the train =?

Solution,

We can solve the question as follows:

It is given that a 120 m long train crosses the platform double its length in 30 seconds. We have to find the speed of the train.

$Length\: of\: the\: train = 120\: m$

$Time = 30\: seconds$

When an object travels a given distance at a given time, the formula for finding the speed is given as:

$Speed = \frac{Distance}{Time}$

Now,

The total distance traveled by the train will be equal to the length of the train and the length of the platform. The length of the platform is double the length of the train. Therefore,

$Length\: of\: the\: platform = 120*2 = 240\: m$

Therefore, the total distance traveled by the train will be:

$Distance = 120 + 240 = 360\: m$

The speed will be:

$Speed = \frac{360}{30}$

          $= 12\: m/s$

Hence, the speed of the train is 12 m/s.