Question

A 1250 kg car is moving down the highway with a velocity of 32.0m/s when it bumps into the car ahead of it which has a mass of 875kg and a velocity of 25.0 m/s. After the collision, the 2 cars stick together. What will be the resulting velocity of the two cars together

Answer 1

Answer:

= 1719.411 m/s

um.....I think it's wrong, but did my best I could.......

Explanation:

found out kinetic energy then found velocity from it........

Answer 2

The resulting velocity of the two cars together is 29.11 m/s.

Explanation:

Given that,

Mass of the car 1, m = 1250 kg

Initial speed of the car 1, u = 32 m/s

Mass of car 2, m' = 875 kg

Initial speed of car 2, u' = 25 m/s

As both cars stick together. It is a case of inelastic collision. Momentum remains conserved. Let V is the resulting velocity of the two cars together. It is given by using conservation of momentum as :

$mu+m'u'=(m+m')V$

$V=\dfrac{mu+m'u'}{(m+m')}$

$V=\dfrac{1250\times 32+875\times 25}{(1250+875)}$

V = 29.11 m/s

So, the resulting velocity of the two cars together is 29.11 m/s. Hence, this is the required solution.

Learn more,

Inelastic collision

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