A 13m long ladder when set against the wall of a house reaches a height of 12m.How far is the foot of the ladder from the wall?
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Answered by
80
Let the ladder be AB=13m
Let the vertical height reached be AC=12m
Let the distance between the foot of the ladder and wall be BC= x meters
By Pythagoras Theorem,
(AB)^2=(AC)^2+(BC)^2
(13)^2=(12)^2+(x)^2
x^2=169-144
x^2=25
x = 5 meters
Therefore,the foot of the ladder is 5 m away from the wall.
Let the vertical height reached be AC=12m
Let the distance between the foot of the ladder and wall be BC= x meters
By Pythagoras Theorem,
(AB)^2=(AC)^2+(BC)^2
(13)^2=(12)^2+(x)^2
x^2=169-144
x^2=25
x = 5 meters
Therefore,the foot of the ladder is 5 m away from the wall.
Answered by
61
Sol)
13 m long ladder = Hypotenuse= 13m
height 12m = Perpendicular
the distance from wall to foot of ladder = base =?
by Pythagoras theorem
H²= B²+ P²
or, 13²= B²+ 12²
or, 169= B²+ 144
or B² = 169 -144
or, B²= 25
or, B = √25
or, B = 5m
therefore foot of ladder is 5m far from wall
hope it helps u
Mark as brainliest
13 m long ladder = Hypotenuse= 13m
height 12m = Perpendicular
the distance from wall to foot of ladder = base =?
by Pythagoras theorem
H²= B²+ P²
or, 13²= B²+ 12²
or, 169= B²+ 144
or B² = 169 -144
or, B²= 25
or, B = √25
or, B = 5m
therefore foot of ladder is 5m far from wall
hope it helps u
Mark as brainliest
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