a. {14 ÷ 2 − (10 ÷ 2)} ÷ 2
b. 12 × 10 − 2[484 − (6 + 3)]
c. 38+ [2 of 7 − {8 ÷ 1 + (11 − 8)}]
d. (5 + 2 − 5)12 − {8 of 3 + 5 1}
e. 6255 − [18+ {6 of (24 ÷ 2 + 2 − 2)}] = there is a vinculum above 2 + 2
f. 121[17- {15-3(7-4)}]
g. 81 of [59- {78+13(10-2 of 5)}]
h. 159- [85- {78+(9-2 of 4)}]
i. 30-52 of 3+(19-3)8
J. 8 + {15-7-(12-6)}-147
Answers
Answered by
0
Step-by-step explanation:
this is a lot of work for only 5 pts. not worth it
Answered by
0
Step-by-step explanation:
this is your
a) part answer
there is lot of questions
I don't have any time to solve
try it by your self
by applying BODMAS rule
B 1st of all solve bracket means jo bhi bracket m phele usse solve kro
O then of means multiply
D divide
M multiply
A addition
S subtraction
Attachments:
Similar questions