Question

a. {14 ÷ 2 − (10 ÷ 2)} ÷ 2
b. 12 × 10 − 2[484 − (6 + 3)]
c. 38+ [2 of 7 − {8 ÷ 1 + (11 − 8)}]
d. (5 + 2 − 5)12 − {8 of 3 + 5 1}
e. 6255 − [18+ {6 of (24 ÷ 2 + 2 − 2)}] = there is a vinculum above 2 + 2

f. 121[17- {15-3(7-4)}]
g. 81 of [59- {78+13(10-2 of 5)}]
h. 159- [85- {78+(9-2 of 4)}]
i. 30-52 of 3+(19-3)8
J. 8 + {15-7-(12-6)}-147

Answer 1

Step-by-step explanation:

this is a lot of work for only 5 pts. not worth it

Answer 2

Step-by-step explanation:

this is your

a) part answer

there is lot of questions

I don't have any time to solve

try it by your self

by applying BODMAS rule

B 1st of all solve bracket means jo bhi bracket m phele usse solve kro

O then of means multiply

D divide

M multiply

A addition

S subtraction