A 1423-kg car is moving along a level highway with a speed of 26.4 m/s. the driver takes the foot off the accelerator and the car experiences a retarding force of 901-n over a distance of 106 m. determine the speed of the car after traveling this distance
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Answered by
17
Force = mass × Acceleration
901 N = 1423 × a
a = 901 / 1423 = 0.6332 m / s²
The car retards so the kinematic equation to use is :
V² = U² - 2as
U = 26.4 m/s
a = 0.6332
S = 106
Substituting in the formula :
V² = 26.4² - 2 × 0.6332 × 106
V² = 696.96 - 134.24
V² = 562.72
V = 23.72 m/s
901 N = 1423 × a
a = 901 / 1423 = 0.6332 m / s²
The car retards so the kinematic equation to use is :
V² = U² - 2as
U = 26.4 m/s
a = 0.6332
S = 106
Substituting in the formula :
V² = 26.4² - 2 × 0.6332 × 106
V² = 696.96 - 134.24
V² = 562.72
V = 23.72 m/s
Answered by
32
Answer:Total length of the x inches long pieces = 4x inches
She has to cut another piece = 7.75 inches
Total length = 4x + 7.75
This is what y represent, so
y = 4x + 7.75
The graph of the equation is continuous
Explanation:
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