Question

A 1423-kg car is moving along a level highway with a speed of 26.4 m/s. the driver takes the foot off the accelerator and the car experiences a retarding force of 901-n over a distance of 106 m. determine the speed of the car after traveling this distance

Answer 1

Force = mass × Acceleration

901 N = 1423 × a

a = 901 / 1423 = 0.6332 m / s²

The car retards so the kinematic equation to use is :

V² = U² - 2as

U = 26.4 m/s

a = 0.6332

S = 106

Substituting in the formula :

V² = 26.4² - 2 × 0.6332 × 106

V² = 696.96 - 134.24

V² = 562.72

V = 23.72 m/s

Answer 2

Answer:Total length of the x inches long pieces = 4x inches

She has to cut another piece = 7.75 inches

Total length = 4x + 7.75

This is what y represent, so

y = 4x + 7.75

The graph of the equation is continuous

Explanation: