A 15 cm long test tube having diameter of 3.6cm has water up to a height of 6cm .20 spherical drops of oil of radius 9mm are dropped into it.what length of the test tube remains empty??plz solv this question l am asking this question second time
Answers
Answer:
Step-by-step explanation:
Length of test tube = 15 cm
diameter of test tube = 3.6 cm
then radius of test tube (r) = 1.8 cm
height of the water in the test tube (h) = 6 cm
Therefore, Volume of water inside test tube = volume of cylinderical test tube of height 6 cm = πr2h
= π × 1.8 × 1.8 × 6
= π × 1810 × 1810 × 6
= π × 95 × 95 × 6= 48625π cm3 radius of one spherical drop of oil (R) = 9 mm =910cm
Therefore volume of one spherical drop
= 43 πR^3 =43π × 910 ×910 ×910=243π250cm^3
Therefore, volume of 20 spherical drops = 20 × 243π250=486π25cm^3
Total volume of water and oil drops = 486π25+486π25=972π25cm^3
Let H be the height of mixture of water and oil in the test tubethen, πr^2H =972π25π × 1.8 × 1.8 × H =972π25⇒1810 × 1810 × H =97225⇒8125 × H =97225⇒H =97225 × 2581 =97281 = 12 cm
The length of test tube that remains empty = 15 − 12 =3 cm.
Answer:
Step-by-step explanation:
Use the picture below and don't mind the handwriting
