Question

A 15 kg  mass is supported by a thin cord attached to a hook in the ceiling. Another cord is attached to the ring of
the mass and pulled horizontally until the supporting cord makes an angle of 30° with the vertical. Find the tensions in both strings.



​

Answer 1

Explanation:

ANSWER

Since the system is in equilibrium;

The moment of forces about point A should be zero.

Thus;

10g×0.5+15g×1=Tsin53

o

×1

50+150=0.8T

T=250 N

At point A, the hinge force is working which can be resolved as R

y

& R

x

R

x

=Tcos 53

o

R

x

=250×0.6=150 N

R

y

=Tsin53

o

R

y

=250×0.8=200 N

R=

(R

x

)

2

+(R

y

)

2

R=

150

2

+200

2

R=250 N

Therefore, The tension in the string will be 250 N and the hinged force at point A will be 250 N