a 150 kg balltravelling at30 m/s,strikes the palm of a player hand and is stopped in 0.05 second .find the force exerted by the ball on the hand?
Answers
Answered by
1
a=v/t
=30/0.05
=600m/s^2
F=ma
=150*600
=90,000N
=30/0.05
=600m/s^2
F=ma
=150*600
=90,000N
Similar questions
Math,
7 months ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago
Physics,
1 year ago
Physics,
1 year ago