Question

A 150 m long train having a constant acceleration crosses a 300m long platform it enters the platform at a speed of 40m\s and leaves it at a speed of 50m\s what os the aceelaration of the train

Answer 1

Total distance covered by the Train = 300 + 150

= 450 m.

Initial velocity of the train = 40 m/s.

Final velocity of the train = 50 m/s.

Using the formula,

v² - u² = 2aS,

where a is the acceleration of the Train.

Substituting the value in the given equation, we will get,

(50)² - (40)² = 2a(450)

2500 - 1600 = 900a

900 = 900a

∴ a = 1 m/s².

Hence, acceleration of the train is 1 m/s².

Hope it helps.

Answer 2

Answer:

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Hi mate

Answer and explanation is in attachment

Hope this helps you