Physics, asked by pathoorisrinivas0, 6 hours ago

A 1500kg car travels north with a speed of
8m {s}^{ - 1}
It slows down to a speed of
2m {s}^{ - 1}
in 3 seconds. Find the acceleration and the force exerted on the car during this time.​

Answers

Answered by bishnucharanajenabis
0

Explanation:

[07/10, 12:14]

[07/10, 12:14]

[07/10, 12:14]

Answered by Anonymous
0

Given:

Mass of car = 1500 kg

u = 8 m/s

v = 2 m/s

t = 3 s

To find:

Acceleration of the car and force exerted on the car.

Solution:

\sf a=\dfrac{v-u}{t}

\sf a=\dfrac{2-8}{3}

\sf a=\dfrac{-4}{3} m/s^{2}

F = ma     - 2nd law of motion

F = \sf 1500 \times (-\dfrac{4}{3} )

F = -500*4

F = -2000 N

Answers:

Acceleration of the car is \sf\dfrac{-4}{3} m/s^{2} (or retardation = \sf\dfrac{4}{3} m/s^{2}) and force exerted on the car is -2000 N (braking force hence it has negative sign; opposite to the direction of motion.)

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