Physics, asked by jabranzeeshan52, 1 month ago

A 150eV increase in an electrons energy changes its de broglie wavelength by two. Calculate the initial de broglie wavelength of the electron​

Answers

Answered by asifeqbal0098
1

Answer:

Pls use this formula and concept

Explanation:

The wavelength λ = h/p is called the de Broglie wavelength, and the relations λ = h/p and f = E/h are called the de Broglie relations. These are the same relations we have for the photon, but for particle E = (1/2)mv2 = p2/(2m), so E = ћ2k2/(2m), λ = h/√(2mE).

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