Question

A 150g ball travelling at 30m/s strike the hand of player and is stopped in 0.06s. Calculate the force

Answer 1

Answer:

Explanation:

Given:

m=150g=0.15kg

u=30m/s

v=0m/s

t=0.06sec

F=mxa

=0.15 * (v-u)/t

=0.15*(0-30)/0.06

=0.15 * -500

= - 75N

PLEASE MARK AS BRAINLIEST

Answer 2

Answer:

Force = - 75 N

Explanation:

Starting velocity = u = 30 m/s

final velocity = v = 0 m/a

time required = t = 0.06 seconds

v - u

acceleration = --------------

t

0 - 30

= -------------

0.06

= - 500

Force = m × a

= 0.150 × (- 500 )

= - 75 N