A 150g ball travelling at 30m/s strikes the palm of a players hand and in stopped in 0.05 seconds. Find the force exerted by the ball on the hand
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Answer:
Given:
m=150g=0.15kg
u=30m/s
v=0m/s
t=0.05sec
F=mxa
=0.15 * (v-u)/t
=0.15*(0-30)/0.05
=3 x -30
=-90N
Step-by-step explanation:
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