Question

A 150g ball travelling at 30m/s strikes the palm of a players hand and in stopped in 0.05 seconds. Find the force exerted by the ball on the hand

Answer 1

Answer:

Given:

m=150g=0.15kg

u=30m/s

v=0m/s

t=0.05sec

F=mxa

=0.15 * (v-u)/t

=0.15*(0-30)/0.05

=3 x -30

=-90N

Step-by-step explanation: