Question

A 150g ball travelling at 30m/s strikes the palm of the player's hand is stop him 0.06 s .find the force exerted by the ball on the hand.

Answer 1

F = mv/t
= [150 g × 10^-3 kg/g × 30 m/s] / (0.06 s)
= 75 N

75 N Force is exerted by ball on the hand

Answer 2

Answer:

75N

Explanation:

mass= 150g= 0.15kg

u=30m/s

v=0m/s

t=0.06 second

force=?

F=m(v-u)/t

=0.15(0-30)/0.06

0.15×-30/0.06

-4.5/0.06

-45×100/6×10

-75N