Question

A 150g ball travelling at 30m/s strikes the palm of the player's hand is stop him 0.05 s .find the force exerted by the ball on the hand.

Answer 1

Given:
m=150g=0.15kg
u=30m/s
v=0m/s
t=0.05sec
F=mxa
=0.15 * (v-u)/t
=0.15*(0-30)/0.05
=3 x -30
=-90N

Answer 2

Answer:

90N

Explanation:

v= 0

u= 30m/s

t= 0.05 sec

mass= 150g

let's convert 150g into kg

1kg =1000g

15/1000=0.15kg

force= m*a

f= 0.15*v-u/t

f=0.15*0-30/0.05

f=3*30

f=90N