Question

a 150gm mass has a velocity (2i+6j)m/s at a certain instant its kinetic energy is

Answer 1

Explanation:

We know that k=

2

1

mv

2

or K=

2

1

m(

v

.

v

)[∵

v

.

v

=v

2

]=

2

1

×(0.150kg)(2

2

+6

2

)=3.0J

Answer 2

Answer:

Kinetic energy = 1/2 mv^2

v^2 = v.v = (2i + 5j).(2i + 5j)

= (4 +25) = 29

mass , m =150 g = 0.15 kg

K.E = 29×0.15/2

= 2.175J

Explanation:

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