Question

A 15m lader reached a window 12 m from the ground on placing it against a wall at a distance a.find the distance of the foot of the ladder from the wall

i need the answer the crt one ​

Answer 1

Answer:

let AB be the wall , BC be the distance of the ladder's foot from the wall & AC be the ladder

AB=12 m

AC=15m

to find :- BC

using Pythagoras theorem we get

(BC)²= (AC)² -(AB)²

$= {15}^{2} - {12}^{2} \\ 225 - 144 = 81 = \sqrt{81} = 9m$

hence the distance of the foot of the ladder from the wall is 9m