A 15m long ladder reached a window 12 m high from the ground on placing it against a wall at q distance a. find the distance of the ladder from the wall.
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Let AC be the ladder and A be the window.
Given: AC=15m, AB=12m, CB=am
In right angled triangle ACB,
(Hypotenuse)
2
=(Base)
2
+[Perpendicular)
2
[By Pythagoras theorem]
⇒(AC)
2
=(CB)
2
+(AB)
2
⇒(15)
2
=(a)
2
+(12)
2
⇒225=a
2
+144
⇒a
2
=225−144=81
⇒a=
81
=9cm
Thus, the distance of the foot of the ladder from the wall is 9m.
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The answer is 9 m
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