A 15m long ladder reached a window 12m high from th ground on placing it against the wall find the distance of the foot of the ladder from the wall .
Answers
Answered by
2
Answer:
9
Step-by-step explanation:
H = 15m P = 12m B =?
Accd.to Pythagoras theorem
H^2 =P^2 +B^2
15^2 =12^2 +B^2
225=144+B^2
225-144=B^2
81=B^2
B = 9
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Answered by
3
Step-by-step explanation:
Pythagorean Therom ⇒ Base² + Height² = Hypotenuse²
⇒ 12² + Height² = 15²
⇒ 144 + Height² = 225
⇒ Height² = 225 - 144
⇒ Height² = 81
⇒ Height = √81
⇒ Height = 9m
∴The distance of the foot of the ladder from the wall is 9m
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