A 15m long ladder reaches a window 12m high from the ground on placing it
against a wall. How far is the foot of the ladder from the wall?
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Answer:
9cm
Step-by-step explanation:
Let AC be the ladder and A be the window.
Given: AC=15m, AB=12m, CB=am
In right angled triangle ACB,
(Hypotenuse) ²=(Base)² +[Perpendicular) ² [By Pythagoras theorem]
⇒(AC) ²=(CB) ²+(AB) ²⇒(15)² =(a) ²+(12) ²
⇒225=a ²+144
⇒a ²=225−144=81
⇒a= 81 =9cm
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