Math, asked by krishnamehta41, 1 year ago

A 15m long ladder reaches a window 12m high from the ground on placing it against a wall. how far is the foot of the ladder from the wall?​

Answers

Answered by BrainlyVirat
17

A 15m long ladder reaches a window 12m high from the ground on placing it against a wall. How far is the foot of the ladder from the wall?

Answer : 9 metres

Refer the attachment for figure.

Step by step explanation :

In given figure,

AC = 15 metres long ladder

AB = 12 metres high

CB = 'a' metres

Now,

∆ ABC is a right angled triangle.

Angle ABC = 90°.

By Pythagoras theorem,

(AC)^2 = (BC)^2 + (AB)^2

(15)^2 = (a)^2 + (12)^2

225 = (a)^2 + 144

225 - 144 = (a)^2

81 = (a)^2

9 = a

Therefore, the foot of the ladder is 9 metres away from the wall.

__________________________

Attachments:
Answered by Anonymous
17
\underline{\mathfrak{\huge{The\:Question\:asked:}}}

A 15 m long ladder reaches a window 12 m high from the ground on placing it against a wall. How far is the foot of the ladder from the wall ?​

\underline{\mathfrak{\huge{Here's \:Your\:Answer:}}}

Refer to the pic attached for the figure of this question.

By the Pythagoras Theorem in Triangle ABC :-

\tt{AB^{2} + CB^{2} = AC^{2}}

Put the values in the formula and then solve it.

\tt{12^{2} + x^{2} = 15^{2}}

Solve it further

\tt{x^{2} = 225 - 144}

Some more steps to go

\tt{x^{2} = 81}

x = 9 m

Answer = 9 m
Attachments:
Similar questions
Math, 7 months ago