Question

A 15pF capacitor is connected to a 60V battery. How much electrostatic energy is stored?

Answer 1

Here given that -

C = 15pF = 15 x 10 ^-12 F

V = 60 volt.

hence by formula ,

U = 1 / 2 × CV2 = 1 / 2 × ( 15 x 10 ^-12 × 60 x 60 )

U = 1 / 2 × ( 54000 x 10 ^-12 )

U = 1 / 2 x ( 54 x 10 ^ -9 )

U = 27 x 10 ^-9 J

Answer 2

Explanation:

Given A 15 pF capacitor is connected to a 60 V battery. How much electrostatic energy is stored?

• Now the potential applied is v = 60 V
• Also given C = 15 pF = 15 x 10^-12
• Therefore electrostatic energy is stored in the capacitor.
• So we have U = 1/2 CV^2
•           So U = 1/2 x 15 x 10^-12 x 60 x 60
• So U = 15 x 10^-12 x 1800
• So U = 27000 x 10^-12
• So U = 2.7 x 10^-8 J

Reference link will be

https://brainly.in/question/18547410