Question

A 17 m ladder leans toa wall and touches the wall at the height of 15 m from the ground find the distance between the foot of the ladder and the wall

Answer 1

hey mate ur ans
17 m ladder becomes hypotenuse
15 m h of wall becomes perpendicular
and apply pythagoraes theorem
distance=√(17^2-15^2)
okkk

Answer 2

here is your answer by Sujeet,
Let to be ABC is right angled triangle at angle B is 90°.

then,
AC(hypotenuse)=17m
AB (perpendicular)=15m
then,
BC(Base)=???

by using pytogoras theorem,
h²=p²+b²
b²=h²-p²
b²=17²-15²
b²=289-225
b²=64
b²=√64
b=8

then, Distance between the foot of ladder and the wall.. 8 metre....



that's all



Sujeet