Question

A 1cm high object is placed at a distance of 2f from a convex lens, what is the height of the image formed.

Answer 1

v-image distance

u-object distance

f-focus

$lens \: formula \\ \frac{1}{v} - \frac{1}{u} = \frac{1}{f} \\ \frac{1}{v} - \frac{1}{ - 2f} = \frac{1}{f} \\ v = \frac{f}{2}$

Now using magnification formula

m=V/U=Height of image/height of object.