A 1m rod of mass 4 kg hangs freely from one end. It is free to rotate about this end. What horizontal force f should be applied at its other end so that it is in equilibrium at an angle of = 300? [hint: draw its weight at the center of the rod, take torques about pivot.]
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One could work out an analytic solution to this problem, but that is not necessary if you just want to be convinced that the advice is good. All the forces on you are your own weight, straight down, and the force the ladder exerts on you. The vertical force which the ladder exerts is upward, so the net force in the vertical direction is smaller than if you were just falling.
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