A 1st order reaction is carried out with an initial concentration of 10 mol per liter and 80%of the reactant is changes into product .now if the same reaction is carried ot wih an initial concentration of 5 mol per liter for the same period the percentage of the reactant changing into product is?
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Solution:
Order of the reaction = 1
Case - 1
Case - 2
Dividing Eq (1) by Eq (2),
On solving it we get,
Now, keeping x = 1 in eq(2), we analyse that Eq (1) = Eq (2). Hence % of reactant changing to product will be same i.e 80%.
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