Physics, asked by jaysingh70, 1 month ago

A 2.0 cm high candle is placed 15 cm in front of a concave mirror with a focal length of 30 cm.

How far "behind" the mirror does the candle appear, and how large is it? (-30 cm, 4 cm)

6. A trucker sees the image of a car passing her truck in her diverging rear-view mirror, whose

focal length is -60 cm. If the car is 1.5 m high and 6.0 m away, what is the size and location of

the image? (13.5 cm, 54 cm​

Answers

Answered by preksha20284
0

Answer:

yaar itna hard

Explanation:

To find the magnification, we can use the equation hi/ho or -di/do where hi is the hight of the image, ho is the height of the object, di is the distance of the image from the mirror, and do is the distance of the object from the mirror. We cannot use hi/ho because we do not know the heights of the image or object, so let's use -di/do.

-60/30=-2

The magnification is -2 times. The negative magnification means the image is inverted. This fits with the previous conclusion that I made that the image will be real, because all real images are be inverted.

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