A 2.0 CM tall object is perpendicular to the principal axis of a convex lens of a focal length 10cm the distance of the object from the length is 15 cm find the image distance and height of the image
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25 cm will be the height
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Object's size (h1) = 2 cm
Focal length of convex lens (f) = 10 cm
Object distance from the lens (u) = -15 cm
Image distance ( v) = ?
Image size (h2) = ?
We know,
1/v - 1/u= 1/f
1/v = 1/f + 1/u
1/v = 1/10 - 1/15
1/v = 1/30
Thus, v = 30 cm
Now, v = 30 cm, 'v' is positive, that means the image is formed on the right side of the lens. That's why it is REAL and INVERTED.
Now, magnification =?
Linear magnification (m) = Size of image / Size of object = h2 / h1 = v/u
m = h2/2 = 30/-15
m= h2 × -15 = 30×2
m = -15 h2 = 60
h2 = 60 / -15
h2 = -4 cm
Size of the image = -4 cm
It's in negative , that means that the image is INVERTED.
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