how many terms arethere in the Ap?7,10,13........151
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Answered by
2
a=7. d=3. an=151 n=?
an=a+(n-1)d
151=7+(n-1)3
151-7=3(n-1)
144/3=(n-1)
n-1=48
n=49
an=a+(n-1)d
151=7+(n-1)3
151-7=3(n-1)
144/3=(n-1)
n-1=48
n=49
Answered by
0
t1= a = 7 , d = 3 , tn = 151
so,
tn= a+(n-1) d
151 = 7 + (n-1) × 3
151- 7= (n-1) ×3
144 = ( n-1) ×3
n-1 = 144/3
n-1 = 48
n = 48 +1
n = 49
so, there are 49 terms in the given A.P
so,
tn= a+(n-1) d
151 = 7 + (n-1) × 3
151- 7= (n-1) ×3
144 = ( n-1) ×3
n-1 = 144/3
n-1 = 48
n = 48 +1
n = 49
so, there are 49 terms in the given A.P
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