Question

A 2.0 CM tall object is placed perpendicular circular to the principal axis of a convex lens of focal length 10cm. the distance of the object from the lens is 15 cm find the nature, position and size of the image also, find its magnification.

Answer 1

ANSWERS :-

Here ,

object size , h1 = 2.0 cm,

object distance, u = – 15 cm,

focal length of convex lens, f = 10 cm

image distance, v = ?

image size h2 = ?

As. 1/v - 1/u = 1/f

1/v = 1/f + 1/u = 1/10 - 1/15 = 3 - 2/30 = 1/30

1/v = 1/30 cm

so,

v = 30 cm .

⚡As v is positive , the image formed is on the right side of the lens. it must be real and inverted.

As linear magnification , m = h2/h1 = v/u,

h2 / 2.0 = 30/-15
or,
-15 h2 = 60
or,
h2 = -4 cm

⚡ Negative sign of m and h2 show that the image is inverted.

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