Question

 A 2.0-kg wood block is placed on a frictionless surface. A spring with a force constant of k = 32.0 N/m is attached to the block, and the opposite end of the spring is attached to the fixed support. The spring can be compressed or extended. The equilibrium position is marked as x = 0.00 m. Work is done on the block, pulling it out to x = + 0.02 m. The block is released from rest and it oscillates between x = + 0.02 m and x = −0.02 m. The period of the motion is 1.57 s. Determine the equations of motion of the system (spring and wood block).​

Answer 1

Explanation:

F = - Kx

m x a = - K x

a = - K/m x

a = - w²x

where w = ✓(K/m)

equation of motio is

d²x/dt²+ w²x = o