Question

A 2.0cm tall object is placed perpendicular to the principal axis of a concave mirror of focal length 10cm the distance of the object from the mirror is 15cm.find the nature position, size of the image.also find magnification​

Answer 1

Answer:

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Answer 2

According to new cartesian sign convention, Object distance, u = -15 cm

Focal length of the concave mirror, f = -10 cm Height of the object, hO=2 cm

According to mirror formula, 1v+1u=1f

⇒1v=1f−1u=1−10−1−15=1−10+115

or v=−30 cm.

The image is formed at a distance of 30 cmfrom the mirror on the same side of the object.It is a real image.

Magnification of the mirror, m=−vu=h1h0

⇒−(−30)−15=hI2⇒h1=−4 cm.

Negative sign shows that image is inverted. The image is real, inverted, of size 4 cm at a distance of 30 cm in front of the mirror.

Solution Image

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