Question

a^2 - 12a +36 factorise using identity​

Answer 1

Answer

(a-6)^2

Step-by-step explanation:

${a}^{2} - 12a + 36 \\ = > {a}^{2} - 6a - 6a + 36 \\ = > a(a - 6) - 6(a - 6) \\ = > (a - 6)(a - 6) \\ = > {(a - 6)}^{2}$

$Note$

• This type of factorization is known as middle term factorization.
• I broke the middle term (12a) into 6a and 6a.
• In the last step I used an identity that is $(a+b)(a+b) =(a+b)^2$ So, $(a-6)(a-6)=(a-6)^2$

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Answer 2

Answer:

a^2-12a-36

= a^2 - 6a - 6a +36

= a(a-6)-6(a-6)

= (a-6)(a-6)

= (a-6)^2

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