Chemistry, asked by alinajosephroy, 1 month ago

a) 2 2 3 N (3.5 g) +H (1.0g) NH p) First reactant is the limiting reagent
b) 2 2 2 H (1.0g) O (4.0g)H O q) Second reactant is the limiting reagent
c) 2 3 S(4.0g) O (6.0g)SO r) Stoichiometric amounts of reactants
d) 2 2 3 Fe (11.2g) + O (3.2g)Fe O s) Mass of reactants > mass of product formeda) 2 2 3 N (3.5 g) +H (1.0g) NH p) First reactant is the limiting reagent
b) 2 2 2 H (1.0g) O (4.0g)H O q) Second reactant is the limiting reagent
c) 2 3 S(4.0g) O (6.0g)SO r) Stoichiometric amounts of reactants
d) 2 2 3 Fe (11.2g) + O (3.2g)Fe O s) Mass of reactants > mass of product formeda) 2 2 3 N (3.5 g) +H (1.0g) NH p) First reactant is the limiting reagent
b) 2 2 2 H (1.0g) O (4.0g)H O q) Second reactant is the limiting reagent
c) 2 3 S(4.0g) O (6.0g)SO r) Stoichiometric amounts of reactants
d) 2 2 3 Fe (11.2g) + O (3.2g)Fe O s) Mass of reactants > mass of product formed

Answers

Answered by itzbhavesh282
0

Answer:

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Explanation:

Answered by llsll0123456
8

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\sqrt{4} = 2 where 2 is a rational number . Here n is perfect square the \sqrt{n} is rational number

\sqrt{5} = 2.236.. is not rational number But it is irrational number.here n is not a perfect square the \sqrt{n} is irrational number

So \sqrt{n} is not irrational number if n is perfect square.

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