a = 2+²+t+1 find 'v' form 3to 5 sec
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i hope you are solve the problem
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1
Answer:
75.33m/s
Explanation:
a = 2t²+t+1
dv/dt = 2t²+t+1
dv = (2t²+t+1)dt
v = {⁵(2t²+t+1)dt
³
v = [2t³/3+t²/2 +t]⁵
³
v = [2(5³)/3+5²/2+5]-[2(3³)/3+3²/2+3]
v = 250/3+25/2+5-18-9/2-3 = 250/3-8 = 226/3
v = 75.33m/s.
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