Question

A 2.20m solution contains 265g of solvent. What is the molality of solution after dilution with an additional 135g of solvent?​

Answer 1

Answer:

duggal ne ka dil kiya manta nhi hu abhi ki nahi hu na ab me jau sone ka to time h mere liye kuch h nhi h ab me sone ke sone ki time hai bahut time lag jata ha h koi kuch bolta to mat kro nhi karni bat kar raha hoo na ji ka birthday diya mera bacha bhai ko to yaad h to kiya karu me hi to h ab mere paas koi value hai ya bata rha hun ji ko aa gaya ji ab tak online rahti h

Answer 2

The molality of the solution after diluting it with the solvent will be 0.675 molal.

Given,

Molality of the solution before diluting=2.20 m

Mass of solvent in the solution before dilution=265 g

Additional mass of the solvent that was added=135 g.

To find,

the molality of solution after dilution with an additional 135g of solvent.

Solution:

• Molality of a substance in as solution is defined as the moles of that substance in 1 Kg of solvent.
• Molality of a substance is temperature independent.
• Its unit is moles/Kg or molal.

Molality=(Moles/Mass of solvent(Kg))

Here,

Molality=(Moles/Mass of solvent(Kg))

$2.20=\frac{Moles}{\frac{135}{1000} } \\2.20=\frac{Moles}{0.135}\\ Moles=0.135X2\\Moles=0.27.$

Moles remain same even after dilution with solvent.

Mass of the solvent=(135+265) g.

The molality of the solution after dilution will be:

Molality=(Moles/Mass of solvent(Kg))

$Molality=\frac{0.27}{\frac{135+265}{1000} } \\Molality=\frac{0.27}{\frac{400}{1000}}\\\\Molality=\frac{0.27}{0.4}\\Molality=0.675 molal.$

The molality of the resultant solution is 0.675 molal.

#SPJ2