Question

A^2-23a+42 solve for class 8

Answer 1

Step-by-step explanation:

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Answer 2

Given: A^2-23a+42

To find: factor of the equation

Step-by-step explanation:

General form of quadratic equation is $ax^2+bx+c$.

Factorization rule

1. First we have to find a pair such that it's product = 42 and sum is = -23 $42=21\times2$ and $7\times6$. Only  one such pair is possible so $21\times2$ .
2. Break the middle term in terms of the sum of a pair of a number such that its product is equal to c .        $a^2-21a-2a+42$
3. Form pair of factor of two pair separately  $a(a-21)-2(a-21)$.
4. Again factor out of remaining sum of product $(a-2)(a-21)$                                                  

Solving equation

$a^2-23a+42$

$a^2-21a-2a+42$

$a(a-21)-2(a-21)$

$(a-2)=0$ and $(a-21)=0$

a = 2 and a = 21