Math, asked by sravya6, 1 year ago

A={2,4,8,16,32,64}in set builder form

Answers

Answered by hruthik2222
35
Given: d={1,2,4,8,16,32,64,128}

It can be seen that 1 = 20, 2 = 21, 4=22 ,8 =23,16=24,32=25,64=26,128=27

∴ {1,2,4,8,16,32,64,128}= {x:x= 2n,n∈N and 0≤n≤ 7}
Answered by mysticd
28

Answer:

Set builder form of set A:

A = {2^{n}:n€N , n ≤6}

Step-by-step explanation:

Given Roster form of set A = {2,4,8,16,32,64}

A = {  2^{1},2^{2},2^{3},2^{4},2^{5},2^{6}}

Set builder form:

If write a set by defining its elements with a "common property" , we can say that the set is in the "set builder form".

Now,

Set builder form of set A:

A = {2^{n}:n€N , n ≤6}

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