Question

a^2-4a+3+2b-b^2 factorise using perfect square

Answer 1

Hola there

Let other factor of the given quadratic expression be a+c.

So, (a+c)(a+b-3) = [math]a^2 - 4a +(3-2b -b^2)[/math]

[math]\Rightarrow \ a^2 + a(b-3+c) + c(b-3) = a^2 - 4a +(3-2b -b^2)[/math]

Comparing the coefficient of 'a' on both the sides:

b+c -3 = -4
c = -1-b
Remember c is the specific value of 'a'.

Clearly, is the other root