Question

(a^2 + 4b^2 - c^2)^2 - 16a^2b^2

Answer 1

$\textbf{\large{\pink{\underline{\underline{Step by step Explanation:-}}}}}$

$\mathtt{(a^{2}+4b^{2}-c^{2})^{2}-16a^{2}b^{2}}$

$\mathtt{=(a^{2}+4b^{2}-c^{2})^{2}-4^{2}a^{2}b^{2}}$

$\mathtt{=(a^{2}+4b^{2}-c^{2})^{2}-(4ab)^{2}}$

$\textit{\underline{ by,,}}$

$\mathbb{[a^{2}-b^{2}=(a+b)(a-b)]}$

$\mathtt{=(a^{2}+4b^{2}-c^{2}+4ab)(a^{2}+4b^{2}-c^{2}-4ab)}$

$\mathtt{=[(a^{2}+4ab+4b^{2})-c^{2}][(a^{2}-4ab+4b^{2})-c^{2}]}$

$\mathtt{=[(a^{2}+2\times a\times 2b+(2b)^{2})-c^{2}][(a^{2}-2\times a\times 2b+(2b)^{2})-c^{2}]}$

$\mathtt{=[(a+2b)^{2})-(c)^{2}][(a-2b)^{2})-(c)^{2}]}$

$\textit{\underline{ by,,}}$

$\mathbb{[a^{2}-b^{2}=(a+b)(a-b)]}$

$\mathtt{=[(a+2b+c)(a+2b-c)][(a-2b+c)(a-2b-c)]}$

❣️$\textbf{\small{\green{\underline{Hope it helps you}}}}$❣️

$\textit{\small{\red{\underline{Please mark it as Brainliest answer...thanks}}}}$

Answer 2

Answer:

(a+2b+c)(a+2b-c)(a-2b+c)(a-2b-c)

Step-by-step explanation: