A
2.5
5
D
In the figure,
seg BD is the bisector of ABC
of AABC.
AB = 5, BC = 7, AD = 2.5,
then CD =
B
7
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Answer:
AB\BC=AD\CD
5/7=2.5/DC
CD=7 X 2.5/5
=7 x 25/50
=7/2
CD=3.5
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