A 2.5 coulomb charge is placed in an electric field where it experiences an electrical force of 50.n. what is the value of the electrical field at the place where the charge is located? remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits to receive full credit.
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its toooooooooooooooooo long
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Answer:
F=Eq
50=E*2.5
50/2.5=E
20 n/c =E
Explanation:
E = F / q
Just divide the force by the charge of the particle.
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