A 2.5 inch diameter disk plate has 8 plate 512 bytes per sector 256 sector 5 surface what is capacity of disk
Answers
Answer:
Explanation:
Given:
Disk = 8 platters * 2 Surfaces =16 platters
each platter = 4084 tracks
each track = 400 sectors
each sector = 1 MB
Calculate:
one track = 400 sectors
= 400 * 1 MB
= 400 MB
one platter = 4084 tracks
= 4084 * 400 MB
= 4 *1024 * 400 MB
= 4 * 400 * 1024 MB
= 4 * 400 GB
= 1600 GB
16 platters = 16 * 1600 GB
= 25600 GB
= 25 * 1024 GB
= 25 TB
The storage capacity of this disk in Bytes = 25 TB
The Capacity of the disk is 25 terabytes.
GIVEN: A 2.5-inch diameter disk plate has 8 plates 512 bytes per sector 256 sectors 5 surfaces.
TO FIND The Capacity of the disk.
SOLUTION:
As we are given in the question,
The diameter of the disk plate is 2.5 inches.
8 plates are present.
512 bytes per sector 256 sector 5 surface
Interpreting the given information,
Disk = 8 platters * 2 Surfaces =16 platters
each platter = 4084 tracks
each track = 400 sectors
each sector = 1 MB
As we know,
one track = 400 sectors
= 400 * 1 MB
= 400 MB
one platter = 4084 tracks
= 4084 * 400 MB
= 4 *1024 * 400 MB
= 4 * 400 * 1024 MB
= 4 * 400 GB
= 1600 GB
Therefore,
16 platters = 16 * 1600 GB
= 25600 GB
= 25 * 1024 GB
= 25 TB
The storage capacity of this disk in Bytes = 25 TB
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