a 2.5 kg stone is released from rest and falls towards to earth after 4 s , the magnitude of its momentum is
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1
Answer:
p=F×t
=2.5×10×4
=100kgm/s
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2
V= gt = 9.8 * 4= 39.2 m/s
MV = 2.5 * 39.2 = 98 kg-m/s
MV = 2.5 * 39.2 = 98 kg-m/s
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