A 2.5 litre flask contains 0.25 mole each of sulphur dioxide and nitrogen gas at 27°c . calculate the partial pressure exerted by each gas and also the total pressure (in Pascal )
Answers
Answered by
46
partial pressure of SO2.
Pso2 = nRt / v
= 0.25 × 8.314 × 300 / 2.5 × 10^-3
= 2.49 × 10^5 Nm^-2 = 2.49 × 10^5 Pa
similarly
Pn2 = 2.49 × 10^5 Pa
following Dalton's law
P total = Pn2 + Pso2
= 2.49 × 10^5 + 2.49 × 10^5
= 4.98 × 10^5 Pa
be create a brainly
Pso2 = nRt / v
= 0.25 × 8.314 × 300 / 2.5 × 10^-3
= 2.49 × 10^5 Nm^-2 = 2.49 × 10^5 Pa
similarly
Pn2 = 2.49 × 10^5 Pa
following Dalton's law
P total = Pn2 + Pso2
= 2.49 × 10^5 + 2.49 × 10^5
= 4.98 × 10^5 Pa
be create a brainly
Similar questions