Question

A 2.50 L flask was used to collect a 5.659 sample of proste gas C3H8.After the sample was collected, the was pressure
was found to be 956 mmHg. What was the tempercare of
the propane in the flask?​

Answer 1

Answer:

A 2.50 L flask was used to collect a 5.65 g sample of propane gas, C3H8. After the sample was collected, the gas pressure was found to be 741 mmHg. What was the temperature of the propane in the flask.

Explanation:

P= 741 mmHg(1 atm/760 mmHg)= .975 atm

V= 2.50 L

n= 5.65 g C3H8 (1 mol/44 g)= .128 mol

R= 0.0821

T= ?

.975(2.50)= .128(0.0821)(T)

2.4375 = .0151(T)

ANSWER:

161.4238 = T