A 2.5cm candle is placed 12cm away from a convex mirror of focal length 30cm. Give the location of the image and the magnification
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Since it is a convex mirror, the image will be virtual i.e. positive, and the focus also will be positive.
Now.
f = 30 cm and u=-12cm
also, h1 (height of object)= 2.5cm
To find v,
1/f=1/v+1/u
=> 1/30=1/v-1/12
=> 1/v=1/30+1/12
=> 1/v= (2+5 ) /60
=> 1/v= 7/60 cm
=> v-= 60/7 cm or 8.57 cm (approx)
And, Magnification of image (m) = -V/u
=> m = -60/7*(-12)
=> m = 5/7 or 0.71 (approx)
also, the height of the image h2 = h1*m
=> h2 = 2.5*0.71
Then, h2 = 1.775 (approx)
Therefore, the height of the image is 1.78 cm (approx)
Now.
f = 30 cm and u=-12cm
also, h1 (height of object)= 2.5cm
To find v,
1/f=1/v+1/u
=> 1/30=1/v-1/12
=> 1/v=1/30+1/12
=> 1/v= (2+5 ) /60
=> 1/v= 7/60 cm
=> v-= 60/7 cm or 8.57 cm (approx)
And, Magnification of image (m) = -V/u
=> m = -60/7*(-12)
=> m = 5/7 or 0.71 (approx)
also, the height of the image h2 = h1*m
=> h2 = 2.5*0.71
Then, h2 = 1.775 (approx)
Therefore, the height of the image is 1.78 cm (approx)
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