Question

a^2+a+1=0 then (a^2-a+1)(a+1-a^2)=?​

Answer 1

Answer:

a^2 + a + 1 = 0

a^2 + a = -1

a(a + 1) = -1

a + 1 = -1/a

i.e, 1/a = -(a + 1) ... (1)

Now,

a^2 + (1/a)^2

= a^2 + [-(a+1)]^2 ... from eq. (1)

= a^2 + a^2 + 2a + 1

= 2(a^2 + a + 1) - 1

As, a^2 + a + 1 = 0

Step-by-step explanation:

Answer 2

Answer:

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